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A gas is contained in a tick-walled balloon. When the pressure changes from 2. 95atm to 2.57 atm. p.
Pressure is a force perpendicular to the unit area on which it is applied.
Given that, P1, the initial pressure is 2.95 atm
The initial volume, V1 = 7.456 L
The final volume, V2 = 4.782 L
The initial temperature, T1 = 379k
The final temperature, T2 = 212k
The equation will be
[tex]\dfrac{P_1V_1}{T_1 } =\dfrac{P_2V_2}{T_2}[/tex]
Putting the values in the equation
[tex]\dfrac{2.95 \times 7.456 L }{379k } =\dfrac{P_2\times 4.782 L}{212k}\\\\\\P_2 = \dfrac{2.95 \times 7.456 L \times 212k }{379k \times 4.782 L} = 2.57\;atm.[/tex]
Thus, the pressure changes from 2. 95atm to 2.57 atm p.
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