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How many moles of water are produced from the following reaction, when 275 kJ of energy is given off?

4 NH3 + 3 O2 → 2 N2 + 6 H2O ΔH = -1530 kJ


Sagot :

The moles of water are produced from the given reaction, when 275 kJ of energy is given off is 1.08 moles.

How do we calculate moles of water?

The mole (symbol mol) is the SI base unit of material quantity. The amount of substance in an object or sample is a measure of how many elementary entities of a certain substance are present.
Given chemical reaction is:

4NH₃ + 3O₂ → 2N₂ + 6H₂O

From the stoichiometry of the reaction it is clear that 6 moles of water molecule is produced.

Actual moles will be calculated by using the enthalpy and energy value as:

Actual moles of H₂O = 275kJ × (6 mol H₂O)/1530kJ) = 1.08 moles.

Hence required moles of H₂O is 1.08 moles.

To know more about moles, visit the below link:

https://brainly.com/question/19099163

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