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a man weights 800n at the earth's surface. What will be the weight of the same person when he is orbiting the earth at double the high of the earth's center

Sagot :

Answer:

200 N

Explanation:

F = G m1 m2 / r^2      G  m1  and m2  are constant for this scenario

             so this becomes

F is proprtional to  1/r^2    

f = 1/r^2

800 = 1/r^2     now change  r  to 2r

  F = 1/(2r)^2 = 1/4 * 1/r^2    <======shows force will be 1/4 of original , or 200N

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