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Sagot :
Answer:
C = 6π in
Step-by-step explanation:
the circumference (C) of a circle is calculated as
C = 2πr ( r is the radius )
the area (A) of a circle is calculated as
A = πr²
given A = 9π , then
πr² = 9π ( divide both sides by π )
r² = 9 ( take square root of both sides )
r = [tex]\sqrt{9}[/tex] = 3
then
C = 2π × 3 = 6π in
given:
[tex]area = 9\pi {in}^{2} [/tex]
to find:
the circumference of the circle in inches in terms of pi.
solution:
[tex]a = {\pi}r^{2} [/tex]
[tex]c = 2\pi \: r[/tex]
[tex]c = \sqrt[2]{a} [/tex]
[tex] c = \sqrt[2]{9} [/tex]
c= 6π in
therefore, the circumference of the circle is 6π in.
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