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24. Evaluate f(x) =
5x+25\
2x^2-50
when x = -5.

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- 1 / 2
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Sagot :

ZMathsidn

Answer:

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Step-by-step explanation:

1. Input x = -5 in function f(x):

[tex]5(-5) + 25 / 2(-5)^{2} - 50[/tex]

[tex]-25+25 / 50 - 50[/tex]

[tex]0/0[/tex]

2. Determine the domain

[tex]0/0[/tex]

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[tex]\Large\textsf{\textbf{Answer\::}}[/tex]

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[tex]\Large\textsf{\textbf{Calculations\::}}[/tex]

Plug in the value of x (-5) and simplify as follows :

[tex]\displaystyle\frac{5(-5)+25}{2(-5)^2-50}[/tex]

[tex]\displaystyle\frac{-25+25}{2(25)-50}[/tex]

[tex]\displaystyle\frac{0}{50-50}[/tex]

[tex]\displaystyle\frac{0}{0}[/tex]

We know that we can't divide by zero. Dividing by zero results in infinity , which is not a number .

So the expression is :

[tex]\textsf{\textbf{und.efined}}[/tex]

[tex]\small\text{hope\:helpful~}[/tex]

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