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The mass of the sample of the material is 0.1664 g.
The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.
By the formula of specific heat
[tex]Q = mc \Delta T[/tex]
Given, that the specific heat (c) of material is 0.416 J/gC
The difference in temperatures is 30°C to 50°C
The mass=?
Q = heat, 50 J
Putting the values in the equation
[tex]\rm 50\;J = m \times 0.416 J/g^\circ C \times (50 - 30)\\\\m = \dfrac{0.416 J/g^\circ C \times 20}{50} = 0.1664 g[/tex]
Thus, the mass of the samples is 0.166 g.
Learn more about specific heat
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