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Sagot :
The height of the tree whose angle of elevation is [tex]74^{0}[/tex] and 54 feet tall is 188 foot.
Height of the tree= 188 foot (rounding off nearest tenth)
What is angle of elevation?
The angle of elevation in math is "the angle formed between the horizontal line and the line of sight when an observer looks upwards is known as an angle of elevation".
We know by trigonometric ratios,
[tex]tan \; \theta = \frac{P}{B}[/tex]
[tex]tan \; 74^0 \;[/tex] = [tex]\frac{P}{54}[/tex]
3.48 = [tex]\frac{P}{54}[/tex]
P= 3.48 x 54
= 187.92 feet
≈ 188 foot (rounding off nearest tenth)
The height of the tree whose angle of elevation is and 54 feet tall is 188 foot.
Learn more about angle of elevation here:
https://brainly.com/question/21137209
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