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What is an equation of the line that passes through the point (-4,-6) and is
parallel to the line 33 – y = 6?

Sagot :

Amphitrite1040idn

Hey there!

33 - y = 6

33 - 1y = 6

-1y + 33 = 6

-y + 33 = 6

SUBTRACT 33 to BOTH SIDES

-y + 33 - 33 = 6 - 33

SIMPLIFY IT!
-y =6 - 33

-y = 6 - 33

-1y = -27

DIVIDE -1 to BOTH SIDES

-1y/-1 = -27/-1

SIMPLIFY IT!
y = -27/-1

y = 27


Therefore, your answer is: y = 27



Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

I guess question is wrong :

What is an equation of the line that passes through the point (-4,-6) and is parallel to the line 33 x– y = 6?

3x - y = 6

[tex]m = \frac{ - a}{b} [/tex]

[tex]m = \frac{ - 3}{ - 1} [/tex]

[tex]m = 1[/tex]

Lines are parallel :

m1 = m2

[tex]x - x1 = m(y - y1)[/tex]

[tex]x + 4= 1(y + 6)[/tex]

[tex]x + 4= y + 6[/tex]

[tex]x - y= 6 - 4[/tex]

[tex]x - y - 2 = 0[/tex]

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