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What is the inverse of y = x2 + 16

Sagot :

Lilytingenidn
y=x2-16
I’m not sure if I’m right or not
Msakerjidn

Answer:

[tex] {y}^{ - 1} = \sqrt{x - 16} [/tex]

Step-by-step explanation:

  • To find the inverse of this function, we make "x" the subject of the equation .
  • [tex]y = {x}^{2} + 16 \\ {x}^{2} = y - 16 \\ x = \sqrt{y - 16} [/tex]
  • then we interchange "y" and "x" .
  • [tex]hence \: the \: inverse \: is \\ {y}^{ - 1} = \sqrt{x - 16} [/tex]
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