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solve for x,
3(x – 4) ≥ 5x + 2

Sagot :

[tex]\Large\textsc{answer :}[/tex]

x≤-7

[tex]\Large\textsc{calculations :}[/tex]

First , use the distributive property :

3(x-4)≥5x+2

3x-12≥5x+2

Subtract 5x on both sides :

3x-5x-12≥2

Now , add 12 on both sides :

3x-5x≥2+12

3x-5x≥14

Subtract the x's :

-2x≥14

Divide by -2 on both sides and watch what happens :

x≤-7 (notice that the inequality sign changed from "greater than or equal to" to "less than or equal to")

If we divide both sides of an inequality by a negative number , we change the inequality sign .

[tex]\footnotesize\textit{hope helpful~}[/tex]

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