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What is an equation of the line that passes through the point (-5,-2) and is parallel to the line x-y=5

Sagot :

Andytran027idn

Answer:

y = x + 3

Step-by-step explanation:

Parallel: x - y = 5 -> y = x - 5

Take the slope from Parallel. m = 1

Point (-5,-2) = (x_0, y_0) ,  m = 1

Point-Slope Form: [tex](y - y_0) = m * (x - x_0)[/tex]

(y - (-2)) = 1 * (x - (-5))

y + 2 = 1x + 5

y = x + 3

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