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Sagot :
Answer:
So, the radius of fifth Bohr orbital of hydrogen is 1. 3225 nm.
Explanation:
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[tex]\\ \rm\Rrightarrow r=0.529\dfrac{n^2}{Z^2}[/tex]
- For hydrogen Z=1
[tex]\\ \rm\Rrightarrow r=0.529(5)²[/tex]
[tex]\\ \rm\Rrightarrow r=0.529(25)[/tex]
[tex]\\ \rm\Rrightarrow r=1.3225nm[/tex]
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