LlMissincrediblellidn
Answered

Join the IDNLearn.com community and start exploring a world of knowledge today. Receive prompt and accurate responses to your questions from our community of knowledgeable professionals ready to assist you at any time.

[tex] \huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red} Question}}}} [/tex]

[tex] \mathfrak \orange{ Refer \: To \: Attachment}[/tex]
​

Tex Hugegreenfcolorboxbluecyanbfunderlineredcolorred Question Textex Mathfrak Orange Refer To Attachmenttex class=

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏxidn

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's find out the gradient (Slope " m ") of line q ;

[tex]\qquad \sf  \dashrightarrow \:m = \dfrac{y_2 - y_1}{x_2 - x_1}[/tex]

[tex]\qquad \sf  \dashrightarrow \:m = \dfrac{4 - 0}{0 - 1}[/tex]

[tex]\qquad \sf  \dashrightarrow \:m = - 4[/tex]

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :

[tex]\qquad \sf  \dashrightarrow \:y - 4 = m(x - 0)[/tex]

[tex]\qquad \sf  \dashrightarrow \:y = mx + 4[/tex]

Now, plug in the value of gradient ~

[tex]\qquad \sf  \dashrightarrow \:y = - 4x + 4[/tex]

here we can clearly observe that, the Area under the curve can easily be represented as :

[tex]\qquad \sf  \dashrightarrow \:y < - 4x + 4[/tex]

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.