Find answers to your questions faster and easier with IDNLearn.com. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.
The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.
The slope of the graph when the potential energy of a particle constrained in on x-axis is determined as follows;
F = -dU/dx
-dU = Fdx
dU = -Fdx
U = -∫(kx + ax³)dx
U = kx²/2 - ax⁴/4
When, x = 0, U = 0
When U = 0;
[tex]x = \pm \sqrt{\frac{2k}{a} }[/tex]
The graph of the potential energy pass through zero origin, cuts across positive x-axis and negative x-axis.
Complete question is below:
Suppose that the potential energy of a particle constrainedon x-axis and subjected to a force in the same direction, at a fuction of F(x) = -kx + ax³.
Find the functional form of the potential energy.
Learn more about potential energy here: https://brainly.com/question/1242059
#SPJ1