Find accurate and reliable answers to your questions on IDNLearn.com. Get comprehensive and trustworthy answers to all your questions from our knowledgeable community members.
Sagot :
The work w required to pump the water out of the spout will be 705600 joules.
What is work done?
Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.
Work against gravity is done on a thin layer of liquid with a width of y. The vertex of the trough serves as the center of our coordinate system.
It is obvious that the cross-section of the triangle has length y at a height y. A thin layer at height y is a rectangular box with a volume of 8 y , and lifting it requires a force equal to;
[tex]\rm F= \rho gV \\\\\rm F= 9.8 \times 10000 \times 8y \triangle y \\\\[/tex]
The work on the layer is;
[tex]\rm W= 78400 y \triangle y [4-y]\\\\\ W= \int\limits^3_0 {x} \, dx \\\\\ W= \int\limits^3_0{78400y[4-y]} \, dx \\\\\ W=705600 \ Joule.[/tex]
Hence, the work w required to pump the water out of the spout will be 705600 joule.
To learn more about the work done, refer to the link ;
https://brainly.com/question/3902440
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.
