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The distance between the two planes 4x-5y+z=16 and 8x-10y+2z=2 will be 2.34 units.
What is a plane?
A plane is a flat surface on which a straight line joining any two points on it would wholly lie.
Given equations are
[tex]4x-5y+z=16[/tex]
[tex]8x-10y+2z=2[/tex]
The distance between two planes is given by the formula:
[tex]D=\dfrac{|d_2-d_1|}{\sqrt{a^2+b^2+c^2}}[/tex]
Here from equations
[tex]4x-5y+z=16[/tex]
[tex]8x-10y+2z=2[/tex]
We can also write the equation [tex]8x-10y+2z=2[/tex] as:
[tex]4x-5y+z=1[/tex]
So now the two equations are:
[tex]4x-5y+z=16[/tex]
[tex]4x-5y+z=1[/tex]
here a=4 b=-5 c =1 and d1=16 d2=1
Putting the values in the equation.
[tex]D=\dfrac{|-16+1|}{\sqrt{4^2+(-5)^2+(10^2)}}[/tex]
[tex]D=2.34[/tex]
Hence the distance between the two planes 4x-5y+z=16 and 8x-10y+2z=2 will be 2.34 units.
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