Get personalized and accurate responses to your questions with IDNLearn.com. Our Q&A platform offers reliable and thorough answers to help you make informed decisions quickly and easily.
Sagot :
The area inside one leaf of the rose: r=6sin(6θ) is 3π/2 after evaluating the integral over the limit 0 to π/6
What is integration?
It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.
We have:
r=6sin(6θ)
First we have to find the limits:
r = 0
6sin(6θ) = 0
θ = nπ/6
n = 0 to n = 1
θ = 0 to θ = π/6
[tex]\rm Area = \int\limits^{\dfrac{\pi}{6}}_0 {6sin6\theta} \, d\theta[/tex]
After calculating the above definite integral, we will get:
Area = 3π/2
Thus, the area inside one leaf of the rose: r=6sin(6θ) is 3π/2 after evaluating the integral over the limit 0 to π/6
Learn more about integration here:
brainly.com/question/18125359
#SPJ4
Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. IDNLearn.com is committed to providing the best answers. Thank you for visiting, and see you next time for more solutions.
