IDNLearn.com provides a reliable platform for finding accurate and timely answers. Ask any question and receive comprehensive, well-informed responses from our dedicated team of experts.
Sagot :
The pH at 25.0 °c of an aqueous solution that is 0. 100 m in acetic acid is 5.744.
What is ka expression?
The acid dissociation constant is the equilibrium constant of an acid's dissociation reaction.
The ka is given [tex]1. 8 \times 10^-^5[/tex]
From the equation pf ka for weak acid
[tex]\rm H^+ = \sqrt{Ka \times C}[/tex]
Putting the values in the equation
[tex]\rm H^+ = \sqrt{ 1. 8 \times 10^-^5 \times 0.100 } = 0.0000018[/tex]
Now, the [tex]\rm pH = -log[H^+][/tex]
[tex]\rm pH = -log[0.0000018] = 5.744[/tex]
Thus, the pH of acetic acid is 5.744
Learn more about ka expression
https://brainly.com/question/16035742
#SPJ4
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.