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Plutonium-32 has a half-life of 14. 2 days. After 99. 4 days, how much of what was originally a 499. 2 gram sample remains?

Sagot :

The amount of sample of Plutonium-32 which is remained after 99.4 days is 3.9 grams.

How do we calculate the remaining amount?

Remaining amount of any substance after the decay will be calculated by using the below equation:

N = N₀[tex](\frac{1}{2})^{\frac{T}{t}}[/tex], where

N = remained quantity = ?

N₀ = original quantity = 499.2g

T = total time = 99.4 days

t = half life time = 14.2 days

T/t = 99.4/14.2 = 7

On putting all these values in the above equation, we get

N = (499.2)(0.5)⁷

N = (499.2)(0.0078) = 3.9g

Hence remaining mass of Plutonium-32 is 3.9 g.

To know more about radioactive law, visit the below link:
https://brainly.com/question/2320811

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