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The amount of maximum mass of ethyl alcohol that could we boil with 1000 J of heat, starting from 20°C is 7.08 grams.
Mass of the ethyl alcohol will be calculated by using the below equation as:
Q = mcΔT, where
On putting all these values, we get
m = 1000 / (2.42)(58.37) = 7.079 = 7.08g
Hence required mass of ethyl alcohol is 7.08grams.
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