IDNLearn.com provides a user-friendly platform for finding answers to your questions. Discover detailed and accurate answers to your questions from our knowledgeable and dedicated community members.
Sagot :
The maximum mass of an object traveling at 479 m⋅s−1 for which the de broglie wavelength is observable, is 3.82×10⁻²⁷ kg.
What is De Broglie equation?
To find the wavelength of a wave, Broglie given an equation. This equation for wavelength is,
[tex]\lambda=\dfrac{h}{mv}[/tex]
Here, (h) is the planks constant, m is mass and (v) is the velocity.
Assuming that the smallest measurable wavelength in an experiment is 0. 450 fm. The speed of the object is 479 m⋅s−1.
Put the values in the formula,
[tex]\lambda=\dfrac{h}{mv}\\ 0.450\times10^{-15}=\dfrac{6.63\times10^{-34}}{m\times479}\\m=3.07\times10^{-21}\rm \;kg[/tex]
Thus, the maximum mass of an object traveling at 479 m⋅s−1 for which the de broglie wavelength is observable, is 3.82×10⁻²⁷ kg.
Learn more about the De Broglie equation here;
https://brainly.com/question/19131384
#SPJ4
Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.