Get comprehensive solutions to your problems with IDNLearn.com. Discover comprehensive answers to your questions from our community of experienced professionals.
Sagot :
The maximum mass of an object traveling at 479 m⋅s−1 for which the de broglie wavelength is observable, is 3.82×10⁻²⁷ kg.
What is De Broglie equation?
To find the wavelength of a wave, Broglie given an equation. This equation for wavelength is,
[tex]\lambda=\dfrac{h}{mv}[/tex]
Here, (h) is the planks constant, m is mass and (v) is the velocity.
Assuming that the smallest measurable wavelength in an experiment is 0. 450 fm. The speed of the object is 479 m⋅s−1.
Put the values in the formula,
[tex]\lambda=\dfrac{h}{mv}\\ 0.450\times10^{-15}=\dfrac{6.63\times10^{-34}}{m\times479}\\m=3.07\times10^{-21}\rm \;kg[/tex]
Thus, the maximum mass of an object traveling at 479 m⋅s−1 for which the de broglie wavelength is observable, is 3.82×10⁻²⁷ kg.
Learn more about the De Broglie equation here;
https://brainly.com/question/19131384
#SPJ4
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is your reliable source for accurate answers. Thank you for visiting, and we hope to assist you again.
