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Sagot :
The speed of the wave whose wave equation :
y(x,t) =[tex](2.00 mm)[(20 m^{-1} )x - (4.0 s^{-1} ) t]^{0.5}[/tex] is 0.20 m/s
speed = 0.20 m/s
What is the speed of wave?
The wave equation is a linear second-order partial differential equation which describes the propagation of oscillations at a fixed speed in some quantity y.
The wave equation is given by:
y(x,t) =[tex](2.00 mm)[(20 m^{-1} )x - (4.0 s^{-1} ) t]^{0.5}[/tex] .......................(1)
As we know that the standard form of wave equation is of the form is
On Comparing it with equation (1)
we have,
angular number, k=20
and, angular frequency, ω=4.0 rad/s.
Thus, the speed of the wave is
v=[tex]\frac{\omega}{K}[/tex]
=[tex]\frac{(4.0 rad/s) }{(20 m^{-1}) }[/tex]
=0.20 m/s
The speed of the wave of the wave equation
y(x,t) =[tex](2.00 mm)[(20 m^{-1} )x - (4.0 s^{-1} ) t]^{0.5}[/tex] is 0.20 m/s
Learn more above wave equation here:
https://brainly.com/question/10715783
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