IDNLearn.com is your go-to platform for finding reliable answers quickly. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.
Concentration of vinegar sample of 28mL which requires 21. 5 ml of 0.550 M NaOH to reach the endpoint in a titration is 0.42M.
Concentration of vinegar in the titration method will be used by using the below equation:
M₁V₁ = M₂V₂,
By putting values on above equation from the question, we get
M₂ = (0.55M)(21.5mL) / (28mL) = 0.42 M
Hence, required concentration of vinegar is 0.42M.
To know more about concentration, visit the below link:
https://brainly.com/question/14469428
#SPJ4