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Determine the value of c such that f(x,y) = c(x 2y), x = 1, 2

Sagot :

The value of C is 0.03030 if the f(x, y) = c(x 2y), x = 1, 2 and y =1, 2, 3  because the sum of the probability is always 1

What is a function?

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

f(x, y) = c(x+2y),

x = 1, 2 and y =1, 2, 3

f(1, 1) = C(1 + 2)  = 3C

f(1, 2) = C(1 + 4)  = 5C

f(1, 3) = C(1 + 6)  = 7C

f(2, 1) = C(2 + 2)  = 4C

f(2, 2) = C(2+ 4)  = 6C

f(2, 3) = C(2 + 6)  = 8C

We know the sum of the all probability is 1

3C+5C+7C+4C+6C+8C=1

33C =1

C = 0.03030

Thus, the value of C is 0.03030 if the f(x, y) = c(x 2y), x = 1, 2 and y =1, 2, 3  because the sum of the probability is always 1

Learn more about the function here:

brainly.com/question/5245372

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