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How many grams of nacl are present in 350 ml of a 0. 277 m solution of sodium chloride? a 1. 66 g b 16. 2 g c none of these d 97. 0 g e 5. 67 g

Sagot :

A NaCl solution of 350 mL volume and a concentration of 0.277 M will contain 5.67 grams of the salt.

Mole calculation

Recall that:

Mole = molarity x volume.

Also:

Mass = mole x molar mass

Hence;

Mole of 350 mL, 0.277 NaCl = 0.350 x 0.277 = 0.097 moles

Mass of 0.097 moles NaCl = 0.097 x 58.44 = 5.67 grams

Thus, a 350 mL, 0.277 M NaCl solution will contain 5.67 grams of the salt.

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