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2. At the earth’s surface, a projectile is launched straight up at a speed of 10. 0 km/s. To what height will it rise? ignore air resist

Sagot :

Answer:

5.097 m

Explanation:

H = vo t - 1/2 a t^2

   = 10t - 1/2 (9.81) t^2       max occurs at -b/2a   =  10/9.81=1.0194 sec

  sub in this 't' value to get H =5.097 m

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