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[tex]\sf How \; do \; you\; solve\; this?[/tex]
[tex]\bf 9\left(2x+1\right)=\:9x-18[/tex]

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏxidn

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

[tex] \textbf{Here we go :} [/tex]

[tex]\qquad \sf  \dashrightarrow \:9(2x + 1) = 9x - 18[/tex]

[tex]\qquad \sf  \dashrightarrow \:18x + 9 = 9x - 18[/tex]

[tex]\qquad \sf  \dashrightarrow \:18x - 9x = - 18 - 9[/tex]

[tex]\qquad \sf  \dashrightarrow \:9x = - 27[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = - 27 \div 9[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = - 3[/tex]

[tex] \textsf{Hence, value of x is -3} [/tex]

Dislennyidn
9(2x+1)=9x-18
•Apply the Distributive Property
18x+9=9x-18
•Rearrange variables the the left side of the equation
18x-9x=-18-9
•Combine like terms
9x=-18-9
•Calculate the sum or difference
9x=-27
•Divide both sides
x= -27/-9
•Cross out the common factor

x=-3

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