Explore a diverse range of topics and get answers from knowledgeable individuals on IDNLearn.com. Join our community to receive timely and reliable responses to your questions from knowledgeable professionals.
The height of the mansion that the assassin shot the target from is determined as 1,164.9 ft.
The time of motion of the bullet is calculated as follows;
-h = vsinθ(t) - ¹/₂gt²
-6.1 = (vt) sin63 - ¹/₂(32)t²
-6.1 = 0.89vt - 16t² ---(1)
X = vcosθ t
294 = (vt)cos63
294 = 0.454vt
vt = 294/0.454
vt = 647.577 ---(2)
solve (1) and (2) together;
-6.1 = 0.89(647.577) - 16t²
16t² = 576.344 + 6.1
16t² = 582.44
t² = 582.44/16
t² = 36.4
t = √36.4
t = 6.03 s
v = 647.577/t
v = 647.577/6.03
v = 107.4 ft/s
h = vt + ¹/₂gt²
h = (107.4 x sin63 x 6.03) + ¹/₂(32)(6.03)²
h = 1,158.8 ft
H = 1,158.8 ft + 6.1 ft = 1,164.9 ft
Thus, the height of the mansion that the assassin shot the target from is determined as 1,164.9 ft.
Learn more about time of motion here: https://brainly.com/question/2364404
#SPJ1