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1. How many formula units are contained in 270.2 g of zinc nitrate, Zn(NO3)2?
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Zinc nitrate has 1 molecule of zinc (Zn), 2 molecules of nitrogen (N) and 6 molecules of oxygen (O).

Calculate the molecular mass of zinc nitrate by adding the molecular weights for all molecules in the compound.

Here are the molecular weights for each element:

Zn=65.38 g/mol

N=14.01 g/mol

O=16.00 g/mol

The molecular weight of zinc nitrate is then: 1*(65.38)+2*(14.01)+6*(16.00)=189.40 g/mol.

Using a conversion formula to calculate moles of zinc nitrate:

163.97gZn(NO

3

​

)

2

​

∗

189.40gZn(NO

3

​

)

2

​

1molZn(NO

3

​

)

2

​

​

=0.866molZn(NO

3

​

)

2

​

 

There are 0.866 moles of zinc nitrate.

Note: These numbers may vary slightly due to the source of the molecular weight data and the number of decimal places used.
8.588 x 10^23 formula units
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