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find the volume of a cone with a diameter of 18 meters and a height of 20 meters

Sagot :

[tex] \huge \sf \color{pink}{A} \color{green}{N} \color{red}{S} \color{blue}{W} \color{orange}{E} \color{grey}{R}[/tex]

[tex]\large \underline{ \boxed{ \sf{✰ \: Important \: points }}}[/tex]

[tex] \pink{➢}[/tex] Diameter of cone = 18m

[tex] \pink{➢}[/tex]Height of cone = 20m

[tex] \pink{➢}[/tex]A surface of revolution formed by rotating a segment of a line around another line that intersects the first line.

[tex] \pink{➢}[/tex]Cone is basically formed by circular base

[tex]\underline{ \boxed{ \sf{➫\: Volume\:of\:cone = \frac{1}{3} {r}^{2} \pi \: h}}}[/tex]

[tex]\underline{ \boxed{ \sf{ ➪ \: r = radius}}} \\\underline{ \boxed{ \sf{ ➪ \: h = height}}}[/tex]

[tex] \pink{➢}[/tex] We know that radius is half of diameter

[tex] \sf \:➩ r = \frac{18}{2} \\ \sf \: ➩r = \cancel \frac{18}{2} \\ \sf \: ➩r = 9 \: \: \: [/tex]

[tex] \pink{➢}[/tex]Hence radius of cone in data given is 9m

➢ Let's substitute values according to formula

[tex]\sf \: → \frac{1}{3} \times {(9)}^{2}\times 3.14 \times20 \\ \sf→ \frac{1}{3} \times 81 \times 3.14 \times 20 \\ \sf \: → \frac{1}{ \cancel3} \times \cancel{81} \times 3.14 \times 20 \\ \sf→27 \times 3.14 \times 20 \\ \sf \: →1695.6m[/tex]

[tex] \pink{➢}[/tex] Hence volume of cone =1695.6m

Hope it helps !