IDNLearn.com is the perfect place to get detailed and accurate answers to your questions. Our platform offers comprehensive and accurate responses to help you make informed decisions on any topic.
Sagot :
Not Answer:
8
Step-by-step Non-explanation:
The first term ( -4.9(t-4)^2 ) can never be positive, so the maximum height of 80 meters is achieved when t = 4. So the rocket will reach its maximum height after 4 seconds.
The approximate maximum height of the rocket's path is 597.13 meters.
How to elaborate the problem ?
Observer sees the rocket 160 meter away from the place where rocket launched.
75° is the angle between observer and rocket, when the rocket reaches its maximum height.
Here, if we assume a triangle whose base = distance between rocket launch point and the observer.
Height = Maximum height of the rocket
How to calculate the maximum height of the rocket ?
Here, Base = 160 meter & let, maximum height = h
tan 75° = [tex]\frac{height}{base}[/tex]
⇒ tan 75° = [tex]\frac{h}{160}[/tex]
⇒ h = 160 tan 75°
⇒ h = 597.13 (approx)
The maximum height of the rocket is 597.13 meters (approx).
Learn more about Height base problem here :
https://brainly.com/question/27565225
#SPJ2
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.
