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An observer 160 meters away sees a rocket launch into the
air. The rocket reaches its maximum height when the ob-
server is looking at an angle of 75° relative to the ground.
What is the approximate maximum height of the rocket's
path, in meters?

Sagot :

Not Answer:

8

Step-by-step Non-explanation:

The first term ( -4.9(t-4)^2 ) can never be positive, so the maximum height of 80 meters is achieved when t = 4. So the rocket will reach its maximum height after 4 seconds.

Varshamittal029idn

The approximate maximum height of the rocket's path is 597.13 meters.

How to elaborate the problem ?

Observer sees the rocket 160 meter away from the place where rocket launched.

75° is the angle between observer and rocket, when the rocket reaches its maximum height.

Here, if we assume a triangle whose base = distance between rocket launch point and the observer.

Height = Maximum height of the rocket

How to calculate the maximum height of the rocket ?

Here, Base = 160 meter & let, maximum height = h

tan 75° = [tex]\frac{height}{base}[/tex]

⇒ tan 75° = [tex]\frac{h}{160}[/tex]

⇒ h = 160 tan 75°

⇒ h = 597.13 (approx)

The maximum height of the rocket is 597.13 meters (approx).

Learn more about Height base problem here :

https://brainly.com/question/27565225

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