Connect with a knowledgeable community and get your questions answered on IDNLearn.com. Get the information you need from our community of experts who provide accurate and thorough answers to all your questions.
Sagot :
The difference of the expression [tex]\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}[/tex] is [tex]\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}[/tex]
How to determine the difference?
The expression is given as:
[tex]\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}[/tex]
Factor the denominators of the expressions:
[tex]\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}[/tex]
Apply the difference of two squares to x² - 9
[tex]\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}[/tex]
Take LCM
[tex]\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}[/tex]
Hence, the difference of the expression [tex]\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}[/tex] is [tex]\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}[/tex]
Read more about expressions at:
https://brainly.com/question/723406
#SPJ4
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Trust IDNLearn.com for all your queries. We appreciate your visit and hope to assist you again soon.