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Sagot :
The difference of the expression [tex]\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}[/tex] is [tex]\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}[/tex]
How to determine the difference?
The expression is given as:
[tex]\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}[/tex]
Factor the denominators of the expressions:
[tex]\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}[/tex]
Apply the difference of two squares to x² - 9
[tex]\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}[/tex]
Take LCM
[tex]\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}[/tex]
Hence, the difference of the expression [tex]\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}[/tex] is [tex]\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}[/tex]
Read more about expressions at:
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