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Sagot :
The volume of the conical enclosure is approximately 871 ft³.
The density of the birds in the enclosure is number of birds / volume
The number of bird per cubic ft is 0.04822043628 birds per cubic foot
Volume of a cone
volume of a cone = 1 / 3 πr²h
where
- r = radius
- h = height
Therefore,
v = 1 / 3 × 3.14 × 8² × 13
v = 1 / 3 × 3.14 × 64 × 13
v = 2612.48 / 3
v = 870.826666667
v = 870.83 ft³
The density of the birds in the enclosure is the mass of the birds divided by the volume of the enclosure.
The number of bird per cubic ft is as follows:
density = 42 / 871 = 0.04822043628 birds per cubic foot
learn more on volume here: https://brainly.com/question/27444138
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Answer:
871, number of birds by the volume of the cone, and 0.05.
Step-by-step explanation:
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