Expand your knowledge base with the help of IDNLearn.com's extensive answer archive. Find in-depth and trustworthy answers to all your questions from our experienced community members.

Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2? f(x) = –x2 – 8x – 16 f(x) = –x2 8x – 16 f(x) = –x2 – 8x 16 f(x) = –x2 8x 16

Sagot :

Using the Factor Theorem, the second degree polynomial function that has a leading coefficient of –1 and root 4 with multiplicity 2 is given by:

f(x) = -x² + 8x - 16

What is the Factor Theorem?

The Factor Theorem states that a polynomial function with roots [tex]x_1, x_2, \codts, x_n[/tex] is given by:

[tex]f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)[/tex]

In which a is the leading coefficient.

In this problem, we have that:

  • The leading coefficient is of a = -1.
  • There is a root of 4 with multiplicity 2, hence [tex]x_1 = x_2 = 4[/tex].

Thus, the polynomial is given by:

f(x) = -(x - 4)(x - 4)

f(x) = -(x² - 8x + 16)

f(x) = -x² + 8x - 16

More can be learned about the Factor Theorem at https://brainly.com/question/24380382

#SPJ4

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.