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Sagot :
Answer:
Step-by-step explanation:
wow, they really try to make these probablity questions difficult. so they say 5 but really, b/c the 1st one is heads , we are tossing the coin 4 more times, to find 3 heads b/c we already got one. wow, I'm mad at the teacher that asked this. :P Just say 4 flips for 3 heads.
P(H) = heads
P(H) =1/[tex]2^{4}[/tex] probability is 1/[tex]2^{4}[/tex] because we have two outcomes and four tries.
P(H) = 1/16
P(H>=3) 3 * 1/16
P(H>=3) = 3/16
if there is an argument that you have to take 1/[tex]2^{5}[/tex] into account by the teacher tell them that it was already resolved , the first flip is not a "probablity" any longer. It's heads, 100% , it doesn't affect the next tosses b/c this is a "fair" coin and it's going to land on heads 50% of the time, for every toss. Just my rant. :P
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