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Sagot :
Answer:
is this not biology? Capture and recapture method of data collection?
Answer:
Part A:
Fraction: 5400/5625
Decimal Number: 0.96
Percentage: 96%
Part B:
The likely hood of the next elk being unmarked is 96/100= 0.96 as 0.96 is close to 1 it is very likely that the next elk will probably be unmarked.
Part C:
A simulation that could model this situation would be:
Take a number from 1 to 100
If it is between 1-96 it would mean that the Elk was unmarked.
If it would be 97-100 it would mean that the Elk was already marked.
Part D:
Fraction: 696/928
Decimal Number: 0.75
Percentage: 75%
Part E:
The likely hood of the next wolf being unmarked is 75/100= 0.75 as 0.75 is close to 1 it is likely that the next wolf will probably be unmarked.
Part F:
You could use a spinner and divide the spinner into 4 colors, Red, Blue, Orange, Yellow. Yellow, Orange, and Red would represent the next wolf being unmarked, and Blue would represent the next wolf being marked.
Part G:
Probability: 52/100 = 0.52 = 52%
Part H:
The likely hood of the next bear and cougar being unmarked is 52/100 = 0.52 as 0.52 is not close nor far away from 1 it is neither likely nor unlikely that the next bear and cougar will be unmarked.
Part I:
You could ask a computer for a number between 1-100
Number 1-52 equals the cougar and bear caught both being unmarked.
Number 53-100 equals either the cougar or bear caught being marked.
Part J:
The probability of the mountain goat, deer, and moose being caught unmarked is 21%
Part K:
The likely hood of the next mountain goat, deer, and moose being unmarked is 21/100 = 0.21 as 0.21 is not close away from 1 it is unlikely that the next mountain goat, deer, and moose will be unmarked.
Part L:
You could use a random number generator to generate numbers between 1-100.
1-21 means that mountain goat, deer, and moose are caught unmarked
22-100 means that mountain goat, deer, and moose are caugth marked.
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