Answer:
[tex]y=-\dfrac{300}{7}x+1000[/tex]
Step-by-step explanation:
Method 1 (see attachment 1 with red line)
Plots the points on a graph and draw a line of best fit, remembering to ensure the same number of points are above and below the line.
Use the two end-points of the line of best fit to find the slope:
[tex]\textsf{let}\:(x_1,y_1)=(0,1000)[/tex]
[tex]\textsf{let}\:(x_2,y_2)=(7,700)[/tex]
[tex]\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{700-1000}{7-0}=-\dfrac{300}{7}[/tex]
Input the found slope and point (0, 1000) into point-slope form of a linear equation to determine the equation of the line of best fit:
[tex]\implies y-y_1=m(x-x_1)[/tex]
[tex]\implies y-1000=-\dfrac{300}{7}(x-0)[/tex]
[tex]\implies y=-\dfrac{300}{7}x+1000[/tex]
Method 2 (see attachment 2 with blue line)
If you aren't able to plot the points, you should be able to see that the general trend is that as x increases, y decreases. Therefore, take the first and last points in the table and use these to find the slope:
[tex]\textsf{let}\:(x_1,y_1)=(1,940)[/tex]
[tex]\textsf{let}\:(x_2,y_2)=(7,710)[/tex]
[tex]\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{710-940}{7-1}=-\dfrac{115}{3}[/tex]
Input the found slope and point (1, 940) into point-slope form of a linear equation to determine the equation of the line of best fit:
[tex]\implies y-y_1=m(x-x_1)[/tex]
[tex]\implies y-940=-\dfrac{115}{3}(x-1)[/tex]
[tex]\implies y=-\dfrac{115}{3}x+\dfrac{2935}{3}[/tex]
