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What volume is occupied by a 0.118 mol of helium gas at a pressure of 0.97 atm and a temperature of 305 K ? Would the volume be different if the gas was argon (under the same conditions) ?

Sagot :

Answer:

See below

Explanation:

PV = n RT        R = .082057  L - Atm / (K-Mole)

.97 V = .118 (.082057)(305)    

    V = 3.04 liters

Will not change for argon.....will be the same for all ideal gases