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What is the vertex of the quadratic function f(x) = (x-8)(x - 2)?

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Altavistardidn

Answer:

The vertex is (5, -9).

Step-by-step explanation:

One way of approaching this problem consists of finding the roots.  Seet the quadratic equal to zero and solve for x:  {2, 8}.

The axis of symmetry is exactly halfway between 2 and 8:  x = 5.

Now find the y-component of the vertex by evaluating f(5):

f(5) = (5 - 8)(5 - 2) = -9

The vertex is (5, -9).  This is the minimum value of the function.  The graph of this quadratic opens up.

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