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Sagot :
Answer:
For 1hour whole milk feed = (60,000 /6 )Kg=10,000Kg
So that the flow rate of whole milk feed = 10,000 kg/hr
Mass of whole milk=10,000 kg
Mass of cream = x kg Mass of skim milk=(1-x) Mass balance equation is Whole milk= skim milk + cream 10,000kg=skim milk + x kg So, skim milk = (10,000-x) kg Material balance on fat is 10,000kg×0.04 = (10,000-x)×0.004 + x On solving the above equation we get the value of x So, x=361.44 kg So that the flow rate of cream = x= 361.44kg/hr and mass of skim milk= (10,000-x)=(10,000-361.44)kg = 9,638.56 kg So that the flow rate of skim milk = 9,638.56 kg/hr. for checking
(Whole milk) flow rate = (skim milk + cream) flow rate
10,000 kg/hr = (9,638.56 + 361.44) kg/hr 10,000 kg/hr = 10,000 kg/hr Hence it is proved.
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