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At 25°C and 1.0 atm, 0.84 g of a gas dissolves in 2.00 L of water. What mass of the gas dissolves
in 1.00 L of water at 25°C and 3.0 atm?

Sagot :

Lanuelidn

The mass of the gas dissolved in 1.00 L of water at 25°C and 3.0 atm is equal to 1.26 grams.

How to determine the mass of the gas dissolved?

In order to determine the mass of the gas dissolved, we would the calculate the new (final) solubility of this gas by applying this formula:

S₁P₂ = S₂P₁

Making S₂ the subject of formula, we have:

S₂ = (S₁P₂)/P₁

S₂ = (0.42 × 3.0)/1.0

S₂ = 1.26 g/L.

Now, we can determine the mass:

Mass = solubility × volume

Mass = 1.26 × 1.00

Mass = 1.26 grams.

Read more on solubility here: https://brainly.com/question/3006391

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