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What are the zeros oh g(x)=x(x+1)(x-2)^2

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Loneguyidn

[tex]~~~~~x(x+1)(x-2)^2 =0\\\\\implies x = 0~~ \text{or}~~ x +1 = 0~~ \text{or}~~ (x-2)^2 = 0\\\\\implies x = 0, ~ x = -1 , ~x=2\\\\\text{Hence the roots are}~0,-1 ,~2[/tex]

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