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What is the range of y=-3x+1 for the domain of {2, 8}

Sagot :

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Answer:

[0,∞), {y|y≥0}

Step-by-step expl

The graph of y =|3x + 1| is attached.

By observation, we can see that the the least y-value that the graph can take is y =0 (i.e the x-axis) and the greatest y-value that the graph can take is positive infinity.

Hence the range is [0,∞), {y|y≥0}

Reinhard10158idn

Step-by-step explanation:

the domain is the set or interval of all valid x-values.

the range is the set of interval of all valid y-values.

the function is a line function, so it's values will continuously increase with increasing x-valies.

therefore we can simply take the 2 interval ends of the domain as the x-values that create the lowest and the highest functions value in that interval.

the function does not make any large twists and turns in that interval.

y = 3x + 1

for x = 2

y = 3×2 + 1 = 6 + 1 = 7

for x = 8

y = 3×8 + 1 = 24 + 1 = 25

so, the range is [7, 25]

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