Answered

IDNLearn.com offers a comprehensive solution for finding accurate answers quickly. Ask anything and receive well-informed answers from our community of experienced professionals.

Calculate the pH of the following solutions at 298 K.
a) 0.25 mol dm-3 HCl.​​​​​​​​
b) 0.15 mol dm-3 H2SO4.​​​
c) 0.15 mol dm-3 benzoic acid. Ka(benzoic acid) = 6.4 x 10-5 mol dm-3.
d) 0.10 mol dm-3 KOH. Kw(298 K) = 1.0 x 10-14 mol2 dm-6.

Calculate The PH Of The Following Solutions At 298 K A 025 Mol Dm3 HCl B 015 Mol Dm3 H2SO4 C 015 Mol Dm3 Benzoic Acid Kabenzoic Acid 64 X 105 Mol Dm3 D 010 Mol class=

Sagot :

Pstnonsonjokuidn

The term pH has to do with the hydrogen ion concentration of a solution.

What is pH?

The term pH has to do with the hydrogen ion concentration of a solution. Let us now proceed the pH of the solutions;

a) pH of HCl = -log(0.25) = 0.62

b) pH of H2SO4 = -log(0.15) = 0.82

c)  We have to set up an ICE table here;

              C6H5COOH + H2O ⇄ C6H5COO- + H^+

I            0.15                                  0                      0

C          -x                                       +x                     +x

E         0.15 -x                                  x                      x

Ka = [C6H5COO-] [ H^+]/[C6H5COOH]

6.4 x 10^-5 = x^2/0.15 - x  

6.4 x 10^-5(0.15 - x) = x^2

9.6 * 10^-6 - 6.4 x 10^-5x = x^2

x^2 + 6.4 x 10^-5x - 9.6 * 10^-6 = 0

x=0.003 M

Hence;

[C6H5COO-] = [ H^+] = x = 0.003 M

pH = - log[0.003 M] = 2.5

d) [OH-] [H^+] = 1.0 x 10-14 mol2 dm-6

[H^+] = 1.0 x 10-14 mol2 dm-6/ 0.10 mol dm-3

[H^+] = 1 * 10^-13 M

pH= - log[1 * 10^-13 M] = 13

Learn more about pH of a solution:https://brainly.com/question/15289741

#SPJ1

We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.