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Find the 19th term or the arithmetic sequence whose common difference is d=3 and who’s first term is a1=4

Find The 19th Term Or The Arithmetic Sequence Whose Common Difference Is D3 And Whos First Term Is A14 class=

Sagot :

SenorMathWizidn

Answer:

58

Step-by-step explanation:

arithmetic sequence formula : an = a1 + ( n - 1 ) d

where an = nth term , a1 = first term , n = # of terms and d = common difference.

Here, we want to find the 19th term ( so n = 19 ) of an arithmetic sequence whose common difference is 3 ( so d = 3) and whose first term is 4 ( so a1 = 4)

So we have an = a1 + ( n - 1 ) d

n = 19 , a1 = 4 and d= 3

==> plug in values

a19 = 4 + ( 19 - 1 )3

==> subtract 1 from 19

a19 = 4 + (18)3

==> multiply 18 and 3

a19 = 4 + 54

==> add 4 and 54

a19 = 58

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