Answered

IDNLearn.com: Your trusted platform for finding reliable answers. Ask anything and get well-informed, reliable answers from our knowledgeable community members.

2x2 – 9x + 2 = –1
The discriminant is less than 0, so there are two real roots.
The discriminant is less than 0, so there are two complex roots.
The discriminant is greater than 0, so there are two real roots.
The discriminant is greater than 0, so there are two complex roots.

Sagot :

Semsee45idn

Answer:

C)  The discriminant is greater than 0, so there are two real roots

Step-by-step explanation:

Discriminant

[tex]b^2-4ac\quad\textsf{when}\:ax^2+bx+c=0[/tex]

[tex]\textsf{when }\:b^2-4ac > 0 \implies \textsf{two real roots}[/tex]

[tex]\textsf{when }\:b^2-4ac=0 \implies \textsf{one real root}[/tex]

[tex]\textsf{when }\:b^2-4ac < 0 \implies \textsf{no real roots}[/tex]

[tex]2x^2-9x+2=-1[/tex]

[tex]\implies 2x^2-9x+3=0[/tex]

[tex]\implies a=2, b=-9, c=3[/tex]

[tex]\begin{aligned}b^2-4ac &=(-9)^2-4(2)(3)\\& =81-24\\&=57 > 0\implies \textsf{two real roots}\end{aligned}[/tex]

Answer:

C on edge

Step-by-step explanation:

took the test lol

We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Discover the answers you need at IDNLearn.com. Thank you for visiting, and we hope to see you again for more solutions.