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In a certain Algebra 2 class of 26 students, 10 of them play basketball and 5 of them
play baseball. There are 3 students who play both sports. What is the probability that
a
student chosen randomly from the class plays basketball or baseball?
006

Sagot :

K=basketball, S= baseball

10K

5S

3 K & S

26 total

P(K) = 10/26, P(S) = 5/26 P(K^S) = 3/26

P(K v S) = P(K) + P(S) - P(K^S) = 10/26 + 5/26 - 3/26 = 12/26 = 6/13

Probability of randomly getting a student who plays either basketball or baseball = 6/13

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