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In the reaction involving barium iodide and lithium sulfate, the spectator ions would be Li and I.
They are ions found unchanged on both sides of the reactant and the product's sides of reactions.
The reaction of barium chloride and lithium sulfate can be represented by the following ionic equation:
[tex]Ba^+ + 2I^- + 2Li^+ + SO_4^2^- ---- > 2Li^+ + 2I^- + BaSO_4[/tex]
Thus, while [tex]BaSO_4[/tex] precipitate is formed, both [tex]Li^+[/tex] and [tex]I^-[/tex] remain as spectators in the solution.
More on spectator ions can be found here: https://brainly.com/question/22277121
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