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Using the Central Limit Theorem, it is found that the correct option regarding the standard error of the mean is given by:
c. reduce the standard error of the mean to approximately 70% of its current value.
By the Central Limit Theorem, the sampling distribution of sample means of size n has standard error [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
Doubling n, we have that:
[tex]s_d = \frac{\sigma}{\sqrt{2n}} = \frac{1}{\sqrt{2}}\left(\frac{\sigma}{\sqrt{n}}\right) = 0.7\left(\frac{\sigma}{\sqrt{n}}\right) = 0.7s[/tex]
Hence option C is correct.
More can be learned about the Central Limit Theorem at https://brainly.com/question/24663213
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