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The current in two identical light bulbs connected in series is 0. 25 A. The voltage across both bulbs is 110 V. The resistance of a single light bulb is

Sagot :

Ven22514idn

Answer:

220 ohms

Explanation:

I = V / R

0.25 = 110 / R

R = 110 / 0.25

R = 440 ohms

Equivalent resistance = 440 ohms

Resistance of single light bulb = Equivalent resistance / number of bulbs

= 440 / 2

= 220 ohms

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